ardour/livetrax
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Keep tests up to date with reality.

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git-svn-id: svn://localhost/ardour2/branches/3.0@12297 d708f5d6-7413-0410-9779-e7cbd77b26cf
This commit is contained in:
Carl Hetherington 2012-05-15 19:32:39 +00:00
parent 8bdd0304d7
commit c06d747150
1 changed files with 11 additions and 7 deletions
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18
libs/ardour/test/playlist_read_test.cc
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@ -117,7 +117,7 @@ PlaylistReadTest::overlappingReadTest ()
/* ar1's fade in with faded-out ar0 */ /* ar1's fade in with faded-out ar0 */
for (int i = 0; i < 64; ++i) { for (int i = 0; i < 64; ++i) {
/* Similar carry-on to above with float rounding */ /* Similar carry-on to above with float rounding */
float const from_ar0 = (128 + i) * float (1 - float (i / (double) 63)); float const from_ar0 = (128 + i) * float (1 - (i / (double) 63));
float const from_ar1 = i * float (i / (double) 63); float const from_ar1 = i * float (i / (double) 63);
CPPUNIT_ASSERT_DOUBLES_EQUAL (from_ar0 + from_ar1, _buf[i + 128], 1e-16); CPPUNIT_ASSERT_DOUBLES_EQUAL (from_ar0 + from_ar1, _buf[i + 128], 1e-16);
} }
@ -147,12 +147,13 @@ PlaylistReadTest::transparentReadTest ()
_apl->read (_buf, _mbuf, _gbuf, 0, 1024, 0); _apl->read (_buf, _mbuf, _gbuf, 0, 1024, 0);
/* ar0 and ar1 fade-ins; ar1 is on top, so its fade in will implicitly /* ar0 and ar1 fade-ins; ar1 is on top, but it is transparent, so
fade in ar0 its fade in will not affect ar0; ar0 will just fade in by itself,
and the two will be mixed.
*/ */
for (int i = 0; i < 64; ++i) { for (int i = 0; i < 64; ++i) {
float const fade = i / (double) 63; float const fade = i / (double) 63;
float const ar0 = i * fade * (1 - fade); float const ar0 = i * fade;
float const ar1 = i * fade; float const ar1 = i * fade;
CPPUNIT_ASSERT_DOUBLES_EQUAL (ar0 + ar1, _buf[i], 1e-16); CPPUNIT_ASSERT_DOUBLES_EQUAL (ar0 + ar1, _buf[i], 1e-16);
} }
@ -162,10 +163,13 @@ PlaylistReadTest::transparentReadTest ()
CPPUNIT_ASSERT_DOUBLES_EQUAL (float (i * 2), _buf[i], 1e-16); CPPUNIT_ASSERT_DOUBLES_EQUAL (float (i * 2), _buf[i], 1e-16);
} }
/* ar0 and ar1 fade-outs, mixed (with implicit fade-in of ar0) */ /* ar0 and ar1 fade-outs, mixed */
for (int i = (1024 - 64); i < 1024; ++i) { for (int i = (1024 - 64); i < 1024; ++i) {
float const fade = (1023 - i) / (double) 63; /* Ardour fades out from 1 to VERY_SMALL_SIGNAL, which is 0.0000001,
float const ar0 = i * fade * (1 - fade); so this fade out expression is a little long-winded.
*/
float const fade = (((double) 1 - 0.0000001) / 63) * (1023 - i) + 0.0000001;
float const ar0 = i * fade;
float const ar1 = i * fade; float const ar1 = i * fade;
CPPUNIT_ASSERT_DOUBLES_EQUAL (ar0 + ar1, _buf[i], 1e-16); CPPUNIT_ASSERT_DOUBLES_EQUAL (ar0 + ar1, _buf[i], 1e-16);
} }